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( 2( sin theta cos theta+3)=3 cos theta+4 sin theta ) and ( 0< theta<360^ circ ) then, ( theta= ) ?
1.
2
(
sin
θ
cos
θ
+
3
)
=
3
cos
θ
+
4
sin
θ
2(\sin \theta \cos \theta+\sqrt{3})=\sqrt{3} \cos \theta+4 \sin \theta
2
(
sin
θ
cos
θ
+
3
)
=
3
cos
θ
+
4
sin
θ
and
0
<
θ
<
360
∘
0<\theta<360^{\circ}
0
<
θ
<
36
0
∘
then,
θ
=
\theta=
θ
=
?
RUET 11-12
ক
30
∘
,
150
∘
30^{\circ}, 150^{\circ}
3
0
∘
,
15
0
∘
খ
90
∘
,
0
∘
90^{\circ}, 0^{\circ}
9
0
∘
,
0
∘
গ
60
∘
,
120
∘
60^{\circ}, 120^{\circ}
6
0
∘
,
12
0
∘
ঘ
45
∘
,
135
∘
45^{\circ}, 135^{\circ}
4
5
∘
,
13
5
∘
মক টেস্ট দিন: সমীকরণ সমাধান
( 2( sin theta cos theta+3)=3 cos theta+4 sin theta ) and ( 0< theta<360^ circ ) then, ( theta= ) ? | Suva Ai